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0=15x^2-4x-3
We move all terms to the left:
0-(15x^2-4x-3)=0
We add all the numbers together, and all the variables
-(15x^2-4x-3)=0
We get rid of parentheses
-15x^2+4x+3=0
a = -15; b = 4; c = +3;
Δ = b2-4ac
Δ = 42-4·(-15)·3
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-14}{2*-15}=\frac{-18}{-30} =3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+14}{2*-15}=\frac{10}{-30} =-1/3 $
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